Showing posts with label fermat point. Show all posts
Showing posts with label fermat point. Show all posts
Monday, August 17, 2009
KBB2 Problem 5
In a triangle ABC where AB = 13, BC = 14, CA = 15, a point P is such that $\angle APB = \angle BPC = \angle CPA = 120^0$. Calculate $AP+BP+CP$
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