symmetric 2 variable function

Suppose $S = \{1,2,\dots,n\}$ and $f: S \times S \to R$ satisfies the following: $$f(i,j) + f(j,i) = 0 \forall i,j \in S$$ Now for any two number $i,j$, we say that $i$ is superior to $j$ if there exists a $k$ (not necessarily distinct from $i,j$) such that $f(i,k) + f(k,j) \geq 0$. Show that there exists a number $x \in S$ such that $x$ is superior to all elements of $S$.