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Wednesday, December 2, 2009

Inequality

For positive real number $a,b,c$ prove that

$2\sqrt{ab+bc+ca} \leq \sqrt{3} \sqrt[3]{(a+b)(b+c)(c+a)}$

solution: http://dharmath.thehendrata.com/2009/12/02/solution-inequality/

1 comment:

  1. [...] Original problem: http://dharmath.thehendrata.com/2009/12/02/inequality/ [...]

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